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2/3(x-4)=1/3x+19
We move all terms to the left:
2/3(x-4)-(1/3x+19)=0
Domain of the equation: 3(x-4)!=0
x∈R
Domain of the equation: 3x+19)!=0We get rid of parentheses
x∈R
2/3(x-4)-1/3x-19=0
We calculate fractions
6x/(9x^2-36x)+(-3xx/(9x^2-36x)-19=0
We calculate fractions
We do not support expression: x^3
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