6(c+3)-2=5(c+4)

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Solution for 6(c+3)-2=5(c+4) equation: 



6(c+3)-2=5(c+4)

We move all terms to the left:

6(c+3)-2-(5(c+4))=0

We multiply parentheses

6c-(5(c+4))+18-2=0



We calculate terms in parentheses: -(5(c+4)), so:

5(c+4)

We multiply parentheses

5c+20

Back to the equation:

-(5c+20)



We add all the numbers together, and all the variables

6c-(5c+20)+16=0

We get rid of parentheses

6c-5c-20+16=0

We add all the numbers together, and all the variables

c-4=0

We move all terms containing c to the left, all other terms to the right

c=4

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