2(c+3)=4(c-4)

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Solution for 2(c+3)=4(c-4) equation: 



2(c+3)=4(c-4)

We move all terms to the left:

2(c+3)-(4(c-4))=0

We multiply parentheses

2c-(4(c-4))+6=0



We calculate terms in parentheses: -(4(c-4)), so:

4(c-4)

We multiply parentheses

4c-16

Back to the equation:

-(4c-16)



We get rid of parentheses

2c-4c+16+6=0

We add all the numbers together, and all the variables

-2c+22=0

We move all terms containing c to the left, all other terms to the right

-2c=-22

c=-22/-2

c=+11

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