3(x-4)/2=3(x+12)/10

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Solution for 3(x-4)/2=3(x+12)/10 equation: 



3(x-4)/2=3(x+12)/10

We move all terms to the left:

3(x-4)/2-(3(x+12)/10)=0

We calculate fractions


3x/()+(-(3(x+12)*2)/()=0



We calculate terms in parentheses: +(-(3(x+12)*2)/(), so:

-(3(x+12)*2)/(

We multiply all the terms by the denominator


-(3(x+12)*2)



We calculate terms in parentheses: -(3(x+12)*2), so:

3(x+12)*2

We multiply parentheses

6x+72

Back to the equation:

-(6x+72)



We get rid of parentheses

-6x-72

Back to the equation:

+(-6x-72)



We get rid of parentheses

3x/()-6x-72=0

We multiply all the terms by the denominator


3x-6x*()-72*()=0

We add all the numbers together, and all the variables

3x-6x*()=0

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