x+3+2x=3(x+2)-3

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Solution for x+3+2x=3(x+2)-3 equation: 



x+3+2x=3(x+2)-3

We move all terms to the left:

x+3+2x-(3(x+2)-3)=0

We add all the numbers together, and all the variables

3x-(3(x+2)-3)+3=0



We calculate terms in parentheses: -(3(x+2)-3), so:

3(x+2)-3

We multiply parentheses

3x+6-3

We add all the numbers together, and all the variables

3x+3

Back to the equation:

-(3x+3)



We get rid of parentheses

3x-3x-3+3=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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