4-6(z-2)=4z

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Solution for 4-6(z-2)=4z equation: 



4-6(z-2)=4z

We move all terms to the left:

4-6(z-2)-(4z)=0

We add all the numbers together, and all the variables

-4z-6(z-2)+4=0

We multiply parentheses

-4z-6z+12+4=0

We add all the numbers together, and all the variables

-10z+16=0

We move all terms containing z to the left, all other terms to the right

-10z=-16

z=-16/-10

z=1+3/5

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