3(4b-6)=2(2b+4)-10

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Solution for 3(4b-6)=2(2b+4)-10 equation: 



3(4b-6)=2(2b+4)-10

We move all terms to the left:

3(4b-6)-(2(2b+4)-10)=0

We multiply parentheses

12b-(2(2b+4)-10)-18=0



We calculate terms in parentheses: -(2(2b+4)-10), so:

2(2b+4)-10

We multiply parentheses

4b+8-10

We add all the numbers together, and all the variables

4b-2

Back to the equation:

-(4b-2)



We get rid of parentheses

12b-4b+2-18=0

We add all the numbers together, and all the variables

8b-16=0

We move all terms containing b to the left, all other terms to the right

8b=16

b=16/8

b=2

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