2(3a+5)=3(4a-3)+1

Solution for 2(3a+5)=3(4a-3)+1 equation:

2(3a+5)=3(4a-3)+1

We move all terms to the left:

2(3a+5)-(3(4a-3)+1)=0

We multiply parentheses

6a-(3(4a-3)+1)+10=0


We calculate terms in parentheses: -(3(4a-3)+1), so:

3(4a-3)+1

We multiply parentheses

12a-9+1

We add all the numbers together, and all the variables

12a-8

Back to the equation:

-(12a-8)


We get rid of parentheses

6a-12a+8+10=0

We add all the numbers together, and all the variables

-6a+18=0

We move all terms containing a to the left, all other terms to the right

-6a=-18

a=-18/-6

a=+3