6(1-x)=11x-2(x+2)

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Solution for 6(1-x)=11x-2(x+2) equation: 



6(1-x)=11x-2(x+2)

We move all terms to the left:

6(1-x)-(11x-2(x+2))=0

We add all the numbers together, and all the variables

6(-1x+1)-(11x-2(x+2))=0

We multiply parentheses

-6x-(11x-2(x+2))+6=0



We calculate terms in parentheses: -(11x-2(x+2)), so:

11x-2(x+2)

We multiply parentheses

11x-2x-4

We add all the numbers together, and all the variables

9x-4

Back to the equation:

-(9x-4)



We get rid of parentheses

-6x-9x+4+6=0

We add all the numbers together, and all the variables

-15x+10=0

We move all terms containing x to the left, all other terms to the right

-15x=-10

x=-10/-15

x=2/3

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