5(4x-5)=-21(3-x)

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Solution for 5(4x-5)=-21(3-x) equation:



5(4x-5)=-21(3-x)
We move all terms to the left:
5(4x-5)-(-21(3-x))=0
We add all the numbers together, and all the variables
5(4x-5)-(-21(-1x+3))=0
We multiply parentheses
20x-(-21(-1x+3))-25=0
We calculate terms in parentheses: -(-21(-1x+3)), so:
-21(-1x+3)
We multiply parentheses
21x-63
Back to the equation:
-(21x-63)
We get rid of parentheses
20x-21x+63-25=0
We add all the numbers together, and all the variables
-1x+38=0
We move all terms containing x to the left, all other terms to the right
-x=-38
x=-38/-1
x=+38

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