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7+x=42+x(2*7+x)
We move all terms to the left:
7+x-(42+x(2*7+x))=0
We add all the numbers together, and all the variables
x-(42+x(x+14))+7=0
We calculate terms in parentheses: -(42+x(x+14)), so:We get rid of parentheses
42+x(x+14)
determiningTheFunctionDomain x(x+14)+42
We multiply parentheses
x^2+14x+42
Back to the equation:
-(x^2+14x+42)
-x^2+x-14x-42+7=0
We add all the numbers together, and all the variables
-1x^2-13x-35=0
a = -1; b = -13; c = -35;
Δ = b2-4ac
Δ = -132-4·(-1)·(-35)
Δ = 29
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{29}}{2*-1}=\frac{13-\sqrt{29}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{29}}{2*-1}=\frac{13+\sqrt{29}}{-2} $
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