5z/3z+1=3-2z/3z

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Solution for 5z/3z+1=3-2z/3z equation: 



5z/3z+1=3-2z/3z

We move all terms to the left:

5z/3z+1-(3-2z/3z)=0



Domain of the equation: 3z!=0

z!=0/3

z!=0

z∈R





Domain of the equation: 3z)!=0

z!=0/1

z!=0

z∈R



We add all the numbers together, and all the variables

5z/3z-(-2z/3z+3)+1=0

We get rid of parentheses

5z/3z+2z/3z-3+1=0

We multiply all the terms by the denominator


5z+2z-3*3z+1*3z=0

We add all the numbers together, and all the variables

7z-3*3z+1*3z=0

Wy multiply elements

7z-9z+3z=0

We add all the numbers together, and all the variables

z=0

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