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(5/2)-2g=(5/2)-3+g
We move all terms to the left:
(5/2)-2g-((5/2)-3+g)=0
Domain of the equation: 2)-3+g)!=0We add all the numbers together, and all the variables
g!=0/1
g!=0
g∈R
-2g-((+5/2)-3+g)+(+5/2)=0
We get rid of parentheses
-2g-((+5/2)-3+g)+5/2=0
We calculate fractions
-2g=0
g=0/-2
g=0
Równanie nie ma rozwiązania
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