(50x+80(30-x))/30=60

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Solution for (50x+80(30-x))/30=60 equation: 



(50x+80(30-x))/30=60

We move all terms to the left:

(50x+80(30-x))/30-(60)=0

We add all the numbers together, and all the variables

(50x+80(-1x+30))/30-60=0

We multiply all the terms by the denominator


(50x+80(-1x+30))-60*30=0



We calculate terms in parentheses: +(50x+80(-1x+30)), so:

50x+80(-1x+30)

We multiply parentheses

50x-80x+2400

We add all the numbers together, and all the variables

-30x+2400

Back to the equation:

+(-30x+2400)



We add all the numbers together, and all the variables

(-30x+2400)-1800=0

We get rid of parentheses

-30x+2400-1800=0

We add all the numbers together, and all the variables

-30x+600=0

We move all terms containing x to the left, all other terms to the right

-30x=-600

x=-600/-30

x=+20

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