10/2x+4=4/x=5

Solution for 10/2x+4=4/x=5 equation:

10/2x+4=4/x=5

We move all terms to the left:

10/2x+4-(4/x)=0


Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

10/2x-(+4/x)+4=0

We get rid of parentheses

10/2x-4/x+4=0

We calculate fractions


10x/2x^2+(-8x)/2x^2+4=0

We multiply all the terms by the denominator


10x+(-8x)+4*2x^2=0

Wy multiply elements

8x^2+10x+(-8x)=0

We get rid of parentheses

8x^2+10x-8x=0

We add all the numbers together, and all the variables

8x^2+2x=0

a = 8; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·8·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*8}=\frac{-4}{16}
=-1/4
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*8}=\frac{0}{16}
=0
$