5z+17(2+3z)=16(1+4z)

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Solution for 5z+17(2+3z)=16(1+4z) equation: 



5z+17(2+3z)=16(1+4z)

We move all terms to the left:

5z+17(2+3z)-(16(1+4z))=0

We add all the numbers together, and all the variables

5z+17(3z+2)-(16(4z+1))=0

We multiply parentheses

5z+51z-(16(4z+1))+34=0



We calculate terms in parentheses: -(16(4z+1)), so:

16(4z+1)

We multiply parentheses

64z+16

Back to the equation:

-(64z+16)



We add all the numbers together, and all the variables

56z-(64z+16)+34=0

We get rid of parentheses

56z-64z-16+34=0

We add all the numbers together, and all the variables

-8z+18=0

We move all terms containing z to the left, all other terms to the right

-8z=-18

z=-18/-8

z=2+1/4

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