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(3y+1)-(5y+2)=y-1
We move all terms to the left:
(3y+1)-(5y+2)-(y-1)=0
We get rid of parentheses
3y-5y-y+1-2+1=0
We add all the numbers together, and all the variables
-3y=0
y=0/-3
y=0
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