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=10Y^2-7Y-12
We move all terms to the left:
-(10Y^2-7Y-12)=0
We get rid of parentheses
-10Y^2+7Y+12=0
a = -10; b = 7; c = +12;
Δ = b2-4ac
Δ = 72-4·(-10)·12
Δ = 529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{529}=23$$Y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-23}{2*-10}=\frac{-30}{-20} =1+1/2 $$Y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+23}{2*-10}=\frac{16}{-20} =-4/5 $
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