3(2x-1)+7=6x-3-2(2-2x)

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Solution for 3(2x-1)+7=6x-3-2(2-2x) equation: 



3(2x-1)+7=6x-3-2(2-2x)

We move all terms to the left:

3(2x-1)+7-(6x-3-2(2-2x))=0

We add all the numbers together, and all the variables

3(2x-1)-(6x-3-2(-2x+2))+7=0

We multiply parentheses

6x-(6x-3-2(-2x+2))-3+7=0



We calculate terms in parentheses: -(6x-3-2(-2x+2)), so:

6x-3-2(-2x+2)

determiningTheFunctionDomain
6x-2(-2x+2)-3

We multiply parentheses

6x+4x-4-3

We add all the numbers together, and all the variables

10x-7

Back to the equation:

-(10x-7)



We add all the numbers together, and all the variables

6x-(10x-7)+4=0

We get rid of parentheses

6x-10x+7+4=0

We add all the numbers together, and all the variables

-4x+11=0

We move all terms containing x to the left, all other terms to the right

-4x=-11

x=-11/-4

x=2+3/4

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