3(5-y)=4(3y+2)+27

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Solution for 3(5-y)=4(3y+2)+27 equation: 



3(5-y)=4(3y+2)+27

We move all terms to the left:

3(5-y)-(4(3y+2)+27)=0

We add all the numbers together, and all the variables

3(-1y+5)-(4(3y+2)+27)=0

We multiply parentheses

-3y-(4(3y+2)+27)+15=0



We calculate terms in parentheses: -(4(3y+2)+27), so:

4(3y+2)+27

We multiply parentheses

12y+8+27

We add all the numbers together, and all the variables

12y+35

Back to the equation:

-(12y+35)



We get rid of parentheses

-3y-12y-35+15=0

We add all the numbers together, and all the variables

-15y-20=0

We move all terms containing y to the left, all other terms to the right

-15y=20

y=20/-15

y=-1+1/3

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