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1/3a-20=1/5a
We move all terms to the left:
1/3a-20-(1/5a)=0
Domain of the equation: 3a!=0
a!=0/3
a!=0
a∈R
Domain of the equation: 5a)!=0We add all the numbers together, and all the variables
a!=0/1
a!=0
a∈R
1/3a-(+1/5a)-20=0
We get rid of parentheses
1/3a-1/5a-20=0
We calculate fractions
5a/15a^2+(-3a)/15a^2-20=0
We multiply all the terms by the denominator
5a+(-3a)-20*15a^2=0
Wy multiply elements
-300a^2+5a+(-3a)=0
We get rid of parentheses
-300a^2+5a-3a=0
We add all the numbers together, and all the variables
-300a^2+2a=0
a = -300; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·(-300)·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*-300}=\frac{-4}{-600} =1/150 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*-300}=\frac{0}{-600} =0 $
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