5y-3(-4+1)=2y-(-20)+6

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Solution for 5y-3(-4+1)=2y-(-20)+6 equation: 



5y-3(-4+1)=2y-(-20)+6

We move all terms to the left:

5y-3(-4+1)-(2y-(-20)+6)=0

We add all the numbers together, and all the variables

5y-(2y-(-20)+6)-3(-3)=0

We add all the numbers together, and all the variables

5y-(2y-(-20)+6)+9=0



We calculate terms in parentheses: -(2y-(-20)+6), so:

2y-(-20)+6

determiningTheFunctionDomain
2y+6-(-20)

We add all the numbers together, and all the variables

2y+26

Back to the equation:

-(2y+26)



We get rid of parentheses

5y-2y-26+9=0

We add all the numbers together, and all the variables

3y-17=0

We move all terms containing y to the left, all other terms to the right

3y=17

y=17/3

y=5+2/3

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