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y2+23y=24
We move all terms to the left:
y2+23y-(24)=0
We add all the numbers together, and all the variables
y^2+23y-24=0
a = 1; b = 23; c = -24;
Δ = b2-4ac
Δ = 232-4·1·(-24)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(23)-25}{2*1}=\frac{-48}{2} =-24 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(23)+25}{2*1}=\frac{2}{2} =1 $
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