3-(y+2)=2(6+1)

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Solution for 3-(y+2)=2(6+1) equation: 



3-(y+2)=2(6+1)

We move all terms to the left:

3-(y+2)-(2(6+1))=0

We add all the numbers together, and all the variables

-(y+2)+3-(27)=0

We add all the numbers together, and all the variables

-(y+2)-24=0

We get rid of parentheses

-y-2-24=0

We add all the numbers together, and all the variables

-1y-26=0

We move all terms containing y to the left, all other terms to the right

-y=26

y=26/-1

y=-26

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