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5x-2(2-3x)=5(x-5)-9
We move all terms to the left:
5x-2(2-3x)-(5(x-5)-9)=0
We add all the numbers together, and all the variables
5x-2(-3x+2)-(5(x-5)-9)=0
We multiply parentheses
5x+6x-(5(x-5)-9)-4=0
We calculate terms in parentheses: -(5(x-5)-9), so:We add all the numbers together, and all the variables
5(x-5)-9
We multiply parentheses
5x-25-9
We add all the numbers together, and all the variables
5x-34
Back to the equation:
-(5x-34)
11x-(5x-34)-4=0
We get rid of parentheses
11x-5x+34-4=0
We add all the numbers together, and all the variables
6x+30=0
We move all terms containing x to the left, all other terms to the right
6x=-30
x=-30/6
x=-5
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