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5c^2-32c+12=0
a = 5; b = -32; c = +12;
Δ = b2-4ac
Δ = -322-4·5·12
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{784}=28$$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-28}{2*5}=\frac{4}{10} =2/5 $$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+28}{2*5}=\frac{60}{10} =6 $
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