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x+x(3/100)=1451
We move all terms to the left:
x+x(3/100)-(1451)=0
We add all the numbers together, and all the variables
x+x(+3/100)-1451=0
We multiply parentheses
3x^2+x-1451=0
a = 3; b = 1; c = -1451;
Δ = b2-4ac
Δ = 12-4·3·(-1451)
Δ = 17413
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{17413}}{2*3}=\frac{-1-\sqrt{17413}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{17413}}{2*3}=\frac{-1+\sqrt{17413}}{6} $
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