5x-(x+2)=3-2(x+1)

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Solution for 5x-(x+2)=3-2(x+1) equation: 



5x-(x+2)=3-2(x+1)

We move all terms to the left:

5x-(x+2)-(3-2(x+1))=0

We get rid of parentheses

5x-x-(3-2(x+1))-2=0



We calculate terms in parentheses: -(3-2(x+1)), so:

3-2(x+1)

determiningTheFunctionDomain
-2(x+1)+3

We multiply parentheses

-2x-2+3

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We add all the numbers together, and all the variables

4x-(-2x+1)-2=0

We get rid of parentheses

4x+2x-1-2=0

We add all the numbers together, and all the variables

6x-3=0

We move all terms containing x to the left, all other terms to the right

6x=3

x=3/6

x=1/2

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