7(3n+2)=7(6n+8)+1

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Solution for 7(3n+2)=7(6n+8)+1 equation: 



7(3n+2)=7(6n+8)+1

We move all terms to the left:

7(3n+2)-(7(6n+8)+1)=0

We multiply parentheses

21n-(7(6n+8)+1)+14=0



We calculate terms in parentheses: -(7(6n+8)+1), so:

7(6n+8)+1

We multiply parentheses

42n+56+1

We add all the numbers together, and all the variables

42n+57

Back to the equation:

-(42n+57)



We get rid of parentheses

21n-42n-57+14=0

We add all the numbers together, and all the variables

-21n-43=0

We move all terms containing n to the left, all other terms to the right

-21n=43

n=43/-21

n=-2+1/21

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