4(2n+3)=9(3n+3)+1

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Solution for 4(2n+3)=9(3n+3)+1 equation: 



4(2n+3)=9(3n+3)+1

We move all terms to the left:

4(2n+3)-(9(3n+3)+1)=0

We multiply parentheses

8n-(9(3n+3)+1)+12=0



We calculate terms in parentheses: -(9(3n+3)+1), so:

9(3n+3)+1

We multiply parentheses

27n+27+1

We add all the numbers together, and all the variables

27n+28

Back to the equation:

-(27n+28)



We get rid of parentheses

8n-27n-28+12=0

We add all the numbers together, and all the variables

-19n-16=0

We move all terms containing n to the left, all other terms to the right

-19n=16

n=16/-19

n=-16/19

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