4(2x+3)=9(3x-45)

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Solution for 4(2x+3)=9(3x-45) equation: 



4(2x+3)=9(3x-45)

We move all terms to the left:

4(2x+3)-(9(3x-45))=0

We multiply parentheses

8x-(9(3x-45))+12=0



We calculate terms in parentheses: -(9(3x-45)), so:

9(3x-45)

We multiply parentheses

27x-405

Back to the equation:

-(27x-405)



We get rid of parentheses

8x-27x+405+12=0

We add all the numbers together, and all the variables

-19x+417=0

We move all terms containing x to the left, all other terms to the right

-19x=-417

x=-417/-19

x=21+18/19

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