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5x-(9x+12)=3-(12x-4)
We move all terms to the left:
5x-(9x+12)-(3-(12x-4))=0
We get rid of parentheses
5x-9x-(3-(12x-4))-12=0
We calculate terms in parentheses: -(3-(12x-4)), so:We add all the numbers together, and all the variables
3-(12x-4)
determiningTheFunctionDomain -(12x-4)+3
We get rid of parentheses
-12x+4+3
We add all the numbers together, and all the variables
-12x+7
Back to the equation:
-(-12x+7)
-4x-(-12x+7)-12=0
We get rid of parentheses
-4x+12x-7-12=0
We add all the numbers together, and all the variables
8x-19=0
We move all terms containing x to the left, all other terms to the right
8x=19
x=19/8
x=2+3/8
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