F(x+5)=9x+47

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Solution for F(x+5)=9x+47 equation: 



(F+5)=9F+47

We move all terms to the left:

(F+5)-(9F+47)=0

We get rid of parentheses

F-9F+5-47=0

We add all the numbers together, and all the variables

-8F-42=0

We move all terms containing F to the left, all other terms to the right

-8F=42

F=42/-8

F=-5+1/4

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