7(2x+6)-3(x+5)=20x-43-4(4x-7)

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Solution for 7(2x+6)-3(x+5)=20x-43-4(4x-7) equation: 



7(2x+6)-3(x+5)=20x-43-4(4x-7)

We move all terms to the left:

7(2x+6)-3(x+5)-(20x-43-4(4x-7))=0

We multiply parentheses

14x-3x-(20x-43-4(4x-7))+42-15=0



We calculate terms in parentheses: -(20x-43-4(4x-7)), so:

20x-43-4(4x-7)

determiningTheFunctionDomain
20x-4(4x-7)-43

We multiply parentheses

20x-16x+28-43

We add all the numbers together, and all the variables

4x-15

Back to the equation:

-(4x-15)



We add all the numbers together, and all the variables

11x-(4x-15)+27=0

We get rid of parentheses

11x-4x+15+27=0

We add all the numbers together, and all the variables

7x+42=0

We move all terms containing x to the left, all other terms to the right

7x=-42

x=-42/7

x=-6

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