-2(a+2)-(a-2)=3(a+2)-(a-2)

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Solution for -2(a+2)-(a-2)=3(a+2)-(a-2) equation: 



-2(a+2)-(a-2)=3(a+2)-(a-2)

We move all terms to the left:

-2(a+2)-(a-2)-(3(a+2)-(a-2))=0

We multiply parentheses

-2a-(a-2)-(3(a+2)-(a-2))-4=0

We get rid of parentheses

-2a-a-(3(a+2)-(a-2))+2-4=0



We calculate terms in parentheses: -(3(a+2)-(a-2)), so:

3(a+2)-(a-2)

We multiply parentheses

3a-(a-2)+6

We get rid of parentheses

3a-a+2+6

We add all the numbers together, and all the variables

2a+8

Back to the equation:

-(2a+8)



We add all the numbers together, and all the variables

-3a-(2a+8)-2=0

We get rid of parentheses

-3a-2a-8-2=0

We add all the numbers together, and all the variables

-5a-10=0

We move all terms containing a to the left, all other terms to the right

-5a=10

a=10/-5

a=-2

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