7(x+5)+x=4(x+4)-8

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Solution for 7(x+5)+x=4(x+4)-8 equation: 



7(x+5)+x=4(x+4)-8

We move all terms to the left:

7(x+5)+x-(4(x+4)-8)=0

We add all the numbers together, and all the variables

x+7(x+5)-(4(x+4)-8)=0

We multiply parentheses

x+7x-(4(x+4)-8)+35=0



We calculate terms in parentheses: -(4(x+4)-8), so:

4(x+4)-8

We multiply parentheses

4x+16-8

We add all the numbers together, and all the variables

4x+8

Back to the equation:

-(4x+8)



We add all the numbers together, and all the variables

8x-(4x+8)+35=0

We get rid of parentheses

8x-4x-8+35=0

We add all the numbers together, and all the variables

4x+27=0

We move all terms containing x to the left, all other terms to the right

4x=-27

x=-27/4

x=-6+3/4

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