14(x-2)=4(2x-8)-2(x+4)

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Solution for 14(x-2)=4(2x-8)-2(x+4) equation: 



14(x-2)=4(2x-8)-2(x+4)

We move all terms to the left:

14(x-2)-(4(2x-8)-2(x+4))=0

We multiply parentheses

14x-(4(2x-8)-2(x+4))-28=0



We calculate terms in parentheses: -(4(2x-8)-2(x+4)), so:

4(2x-8)-2(x+4)

We multiply parentheses

8x-2x-32-8

We add all the numbers together, and all the variables

6x-40

Back to the equation:

-(6x-40)



We get rid of parentheses

14x-6x+40-28=0

We add all the numbers together, and all the variables

8x+12=0

We move all terms containing x to the left, all other terms to the right

8x=-12

x=-12/8

x=-1+1/2

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