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5x-(12-3x)=3(x+2)-18
We move all terms to the left:
5x-(12-3x)-(3(x+2)-18)=0
We add all the numbers together, and all the variables
5x-(-3x+12)-(3(x+2)-18)=0
We get rid of parentheses
5x+3x-(3(x+2)-18)-12=0
We calculate terms in parentheses: -(3(x+2)-18), so:We add all the numbers together, and all the variables
3(x+2)-18
We multiply parentheses
3x+6-18
We add all the numbers together, and all the variables
3x-12
Back to the equation:
-(3x-12)
8x-(3x-12)-12=0
We get rid of parentheses
8x-3x+12-12=0
We add all the numbers together, and all the variables
5x=0
x=0/5
x=0
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