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15=1/22x+3x+10
We move all terms to the left:
15-(1/22x+3x+10)=0
Domain of the equation: 22x+3x+10)!=0We add all the numbers together, and all the variables
x∈R
-(3x+1/22x+10)+15=0
We get rid of parentheses
-3x-1/22x-10+15=0
We multiply all the terms by the denominator
-3x*22x-10*22x+15*22x-1=0
Wy multiply elements
-66x^2-220x+330x-1=0
We add all the numbers together, and all the variables
-66x^2+110x-1=0
a = -66; b = 110; c = -1;
Δ = b2-4ac
Δ = 1102-4·(-66)·(-1)
Δ = 11836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11836}=\sqrt{4*2959}=\sqrt{4}*\sqrt{2959}=2\sqrt{2959}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(110)-2\sqrt{2959}}{2*-66}=\frac{-110-2\sqrt{2959}}{-132} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(110)+2\sqrt{2959}}{2*-66}=\frac{-110+2\sqrt{2959}}{-132} $
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