2/x+5=3/2x-3

Solution for 2/x+5=3/2x-3 equation:

2/x+5=3/2x-3

We move all terms to the left:

2/x+5-(3/2x-3)=0


Domain of the equation: x!=0

x∈R



Domain of the equation: 2x-3)!=0

x∈R


We get rid of parentheses

2/x-3/2x+3+5=0

We calculate fractions


4x/2x^2+(-3x)/2x^2+3+5=0

We add all the numbers together, and all the variables

4x/2x^2+(-3x)/2x^2+8=0

We multiply all the terms by the denominator


4x+(-3x)+8*2x^2=0

Wy multiply elements

16x^2+4x+(-3x)=0

We get rid of parentheses

16x^2+4x-3x=0

We add all the numbers together, and all the variables

16x^2+x=0

a = 16; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·16·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*16}=\frac{-2}{32}
=-1/16
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*16}=\frac{0}{32}
=0
$