7(2x+1)=8(x-5)

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Solution for 7(2x+1)=8(x-5) equation: 



7(2x+1)=8(x-5)

We move all terms to the left:

7(2x+1)-(8(x-5))=0

We multiply parentheses

14x-(8(x-5))+7=0



We calculate terms in parentheses: -(8(x-5)), so:

8(x-5)

We multiply parentheses

8x-40

Back to the equation:

-(8x-40)



We get rid of parentheses

14x-8x+40+7=0

We add all the numbers together, and all the variables

6x+47=0

We move all terms containing x to the left, all other terms to the right

6x=-47

x=-47/6

x=-7+5/6

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