5x+40=2x-7+8(x-1)

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Solution for 5x+40=2x-7+8(x-1) equation: 



5x+40=2x-7+8(x-1)

We move all terms to the left:

5x+40-(2x-7+8(x-1))=0



We calculate terms in parentheses: -(2x-7+8(x-1)), so:

2x-7+8(x-1)

determiningTheFunctionDomain
2x+8(x-1)-7

We multiply parentheses

2x+8x-8-7

We add all the numbers together, and all the variables

10x-15

Back to the equation:

-(10x-15)



We get rid of parentheses

5x-10x+15+40=0

We add all the numbers together, and all the variables

-5x+55=0

We move all terms containing x to the left, all other terms to the right

-5x=-55

x=-55/-5

x=+11

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