(z+10)+4z+(z+50)=180

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Solution for (z+10)+4z+(z+50)=180 equation: 



(z+10)+4z+(z+50)=180

We move all terms to the left:

(z+10)+4z+(z+50)-(180)=0

We add all the numbers together, and all the variables

4z+(z+10)+(z+50)-180=0

We get rid of parentheses

4z+z+z+10+50-180=0

We add all the numbers together, and all the variables

6z-120=0

We move all terms containing z to the left, all other terms to the right

6z=120

z=120/6

z=20

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