3x+47-20=24x2

Solution for 3x+47-20=24x2 equation:

3x+47-20=24x^2

We move all terms to the left:

3x+47-20-(24x^2)=0

determiningTheFunctionDomain
-24x^2+3x+47-20=0

We add all the numbers together, and all the variables

-24x^2+3x+27=0

a = -24; b = 3; c = +27;
Δ = b2-4ac
Δ = 32-4·(-24)·27
Δ = 2601
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2601}=51$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-51}{2*-24}=\frac{-54}{-48}
=1+1/8
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+51}{2*-24}=\frac{48}{-48}
=-1
$