3(y-2)+4=(2y+5)

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Solution for 3(y-2)+4=(2y+5) equation: 



3(y-2)+4=(2y+5)

We move all terms to the left:

3(y-2)+4-((2y+5))=0

We multiply parentheses

3y-((2y+5))-6+4=0



We calculate terms in parentheses: -((2y+5)), so:

(2y+5)

We get rid of parentheses

2y+5

Back to the equation:

-(2y+5)



We add all the numbers together, and all the variables

3y-(2y+5)-2=0

We get rid of parentheses

3y-2y-5-2=0

We add all the numbers together, and all the variables

y-7=0

We move all terms containing y to the left, all other terms to the right

y=7

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