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5/8y+8=5+1/2y
We move all terms to the left:
5/8y+8-(5+1/2y)=0
Domain of the equation: 8y!=0
y!=0/8
y!=0
y∈R
Domain of the equation: 2y)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
5/8y-(1/2y+5)+8=0
We get rid of parentheses
5/8y-1/2y-5+8=0
We calculate fractions
10y/16y^2+(-8y)/16y^2-5+8=0
We add all the numbers together, and all the variables
10y/16y^2+(-8y)/16y^2+3=0
We multiply all the terms by the denominator
10y+(-8y)+3*16y^2=0
Wy multiply elements
48y^2+10y+(-8y)=0
We get rid of parentheses
48y^2+10y-8y=0
We add all the numbers together, and all the variables
48y^2+2y=0
a = 48; b = 2; c = 0;
Δ = b2-4ac
Δ = 22-4·48·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-2}{2*48}=\frac{-4}{96} =-1/24 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+2}{2*48}=\frac{0}{96} =0 $
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