4(3x-1)=2(6x-2)

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Solution for 4(3x-1)=2(6x-2) equation: 



4(3x-1)=2(6x-2)

We move all terms to the left:

4(3x-1)-(2(6x-2))=0

We multiply parentheses

12x-(2(6x-2))-4=0



We calculate terms in parentheses: -(2(6x-2)), so:

2(6x-2)

We multiply parentheses

12x-4

Back to the equation:

-(12x-4)



We get rid of parentheses

12x-12x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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