3(3b+2)-12=2(3b-3)

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Solution for 3(3b+2)-12=2(3b-3) equation: 



3(3b+2)-12=2(3b-3)

We move all terms to the left:

3(3b+2)-12-(2(3b-3))=0

We multiply parentheses

9b-(2(3b-3))+6-12=0



We calculate terms in parentheses: -(2(3b-3)), so:

2(3b-3)

We multiply parentheses

6b-6

Back to the equation:

-(6b-6)



We add all the numbers together, and all the variables

9b-(6b-6)-6=0

We get rid of parentheses

9b-6b+6-6=0

We add all the numbers together, and all the variables

3b=0

b=0/3

b=0

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