21x+18=3(5x+4)+6x+6

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Solution for 21x+18=3(5x+4)+6x+6 equation:



21x+18=3(5x+4)+6x+6
We move all terms to the left:
21x+18-(3(5x+4)+6x+6)=0
We calculate terms in parentheses: -(3(5x+4)+6x+6), so:
3(5x+4)+6x+6
We add all the numbers together, and all the variables
6x+3(5x+4)+6
We multiply parentheses
6x+15x+12+6
We add all the numbers together, and all the variables
21x+18
Back to the equation:
-(21x+18)
We get rid of parentheses
21x-21x-18+18=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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