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5(r-2)=2(2+2r)
We move all terms to the left:
5(r-2)-(2(2+2r))=0
We add all the numbers together, and all the variables
5(r-2)-(2(2r+2))=0
We multiply parentheses
5r-(2(2r+2))-10=0
We calculate terms in parentheses: -(2(2r+2)), so:We get rid of parentheses
2(2r+2)
We multiply parentheses
4r+4
Back to the equation:
-(4r+4)
5r-4r-4-10=0
We add all the numbers together, and all the variables
r-14=0
We move all terms containing r to the left, all other terms to the right
r=14
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